-27x^2+75x=0

Solution for -27x^2+75x=0 equation:

-27x^2+75x=0

a = -27; b = 75; c = 0;
Δ = b2-4ac
Δ = 752-4·(-27)·0
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-75}{2*-27}=\frac{-150}{-54}
=2+7/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+75}{2*-27}=\frac{0}{-54}
=0
$